HUB hero image

How to Travel from

Oberlin College to Kenyon College

by Rideshare, Route or Car

Oberlin College
+0
Kenyon College
Transport search to Kenyon College
Oberlin College
+0
Kenyon College
Building a composite car route
Cheapest
Best Offer!
Car
1 h 46 min
127 km.
from $6
Composite Route Car Only

Three ways to Travel from Oberlin College to Kenyon College

Select an Option Below to Start Your Journey
Cheapest
Other

Transport providers

Bus operators

GoBus

Phone:
+1 888 954 6287
Website:
ridegobus.com/
Bus from Wooster to Gambier
Ave. Duration:
1h 15m
Frequency:
Once daily
Estimated price:
$10.22–$12.77

Questions and Answers

What is the cheapest way to get from Oberlin College to Kenyon College?

The cheapest way to get from Oberlin College to Kenyon College is to drive which costs $14.13 - $20.65 and takes 1h 46m.

What is the fastest way to get from Oberlin College to Kenyon College?

The fastest way to get from Oberlin College to Kenyon College is to drive which takes 1h 46m and costs $14.13 - $20.65 .

How far is it from Oberlin College to Kenyon College?

The distance between Oberlin College and Kenyon College is 163 km. The road distance is 127.6 km.

How do I travel from Oberlin College to Kenyon College without a car?

The best way to get from Oberlin College to Kenyon College without a car is to taxi and bus which takes 2h 26m and costs $119.57 - $152.17 .

How long does it take to get from Oberlin College to Kenyon College?

It takes approximately 2h 26m to get from Oberlin College to Kenyon College, including transfers.

What is the time difference between Oberlin College and Kenyon College?

It is currently 03:47 at both, Oberlin College and Kenyon College.

Can I drive from Oberlin College to Kenyon College?

Yes, the driving distance between Oberlin College to Kenyon College is 128 km. It takes approximately 1h 46m to drive from Oberlin College to Kenyon College.

Where can I stay near Kenyon College?

There are 11+ hotels available in Kenyon College. Prices start at $56 per night.
+0